题目
题型:单选题难度:简单来源:不详
A.(0,1) | B.(1,2) | C.(2,3) | D.(3,4) |
答案
求导函数,可得f′(x)=
1 |
xln3 |
∵f(2)=log32+2-3<0,f(3)=log33+3-3>0
∴函数f(x)=log3x+x-3的零点一定在区间(2,3)
故选C.
核心考点
举一反三
A.(1,2) | B.(2,3) | C.(3,4) | D.(5,6) |
A.(0.5,0.6) | B.(0.6,0.7) | C.(0.7,0.8) | D.(0.8,0.9) |
1 |
x |
A.(0,
| B.(
| C.(1,
| D.(
|