题目
题型：不详难度：来源：
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 5 |
| 1 |
| 5 |
| 1 |
| 7 |
| 1 |
| 7 |
| 1 |
| 9 |
答案
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 5 |
| 1 |
| 5 |
| 1 |
| 7 |
| 1 |
| 7 |
| 1 |
| 9 |
…，
an=
| 1 |
| 2n-1 |
| 1 |
| 2n+1 |
故答案为：
| 1 |
| 2n-1 |
| 1 |
| 2n+1 |
核心考点
举一反三
①
2+
|
|
3+
|
|
③
4+
|
|
5+
|
|
（2）你判断完以上各题之后，请猜测你发现的规律，用含n的式子将其规律表示出来，并注明n的取值范围：______．
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 5 |
| 1 |
| 5 |
| 1 |
| 7 |
| 1 |
| 7 |
| 1 |
| 9 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 5 |
| 1 |
| 5 |
| 1 |
| 7 |
| 1 |
| 7 |
| 1 |
| 9 |
| 1 |
| 2n-1 |
| 1 |
| 2n+1 |
| 1 |
| 2n-1 |
| 1 |
| 2n+1 |
2+
|
|
3+
|
|
4+
|
|
5+
|
|