题目
题型:不详难度:来源:
x2 |
9 |
y2 |
4 |
答案
x2 |
9 |
y2 |
4 |
∴焦点坐标为:(
5 |
5 |
∵椭圆的焦点与椭圆
x2 |
9 |
y2 |
4 |
设椭圆的方程为:
x2 |
a2 |
y2 |
b2 |
∵椭圆过点(-3,2),
∴
9 |
a2 |
4 |
b2 |
又∵a2-b2=5,与上式联立解得:a2=15,b2=10,
∴椭圆的标准方程为
x2 |
15 |
y2 |
10 |
故答案为:
x2 |
15 |
y2 |
10 |
核心考点
举一反三
x2 |
a2 |
y2 |
b2 |
4
| ||
3 |
2
| ||
3 |
2 |
| ||
3 |
x2 |
9 |
y2 |
4 |
x2 |
9 |
y2 |
4 |
5 |
5 |
x2 |
9 |
y2 |
4 |
x2 |
a2 |
y2 |
b2 |
9 |
a2 |
4 |
b2 |
x2 |
15 |
y2 |
10 |
x2 |
15 |
y2 |
10 |
x2 |
a2 |
y2 |
b2 |
4
| ||
3 |
2
| ||
3 |
2 |
| ||
3 |