当前位置:初中试题 > 数学试题 > 相似图形性质 > (12分) 如图,在△ABC中,ME和NF分别垂直平分AB和AC.(1)   若BC =" 10" cm,试求△AMN的周长.(2)   在△ABC中,AB =...
题目
题型:不详难度:来源:
(12分) 如图,在△ABC中,MENF分别垂直平分ABAC

(1)   若BC =" 10" cm,试求△AMN的周长.
(2)   在△ABC中,AB = AC,∠BAC = 100°,求∠MAN的度数.
(3) 在 (2) 中,若无AB = AC的条件,你还能求出∠MAN的度数吗?若能,请求出;若不能,请说明理由.
答案

(1)cm
(2)
(3)能,证明略。    
解析

解:(1) ∵ME垂直平分AB
MA = MB·············································································· 1分
NF垂直平分AC
NA = NC··············································································· 2分
cm······················· 4分
(2) ∵AB = AC
······································································· 4分
MA = MB
··································································· 5分
NA = NC
··································································· 6分
·········································· 8分
(3) 能.理由如下:·········································································· 9分
MA = MB
∴∠MAB =B
NA = NB
∴∠NAC =C

·································· 12分
核心考点
试题【(12分) 如图,在△ABC中,ME和NF分别垂直平分AB和AC.(1)   若BC =" 10" cm,试求△AMN的周长.(2)   在△ABC中,AB =】;主要考察你对相似图形性质等知识点的理解。[详细]
举一反三
三角形第一边长为a + b,第二、三边的长分别比第一边长大a – 5和2b,则这个三角形的周长为(   )
A.2a + 3b – 5B.C.D.

题型:不详难度:| 查看答案
用火柴棍搭三角形,如下图:

1个       2个                3个                     4个   …
请你找出规律猜想搭个三角形需要__________根火柴棍。
题型:不详难度:| 查看答案
如图,△ABC与△A/ B/ C/关于直线MN对称,P为MN上任意一点,下列说法不正确的是 (    )
A.AP=A/P
B.MN垂直平分A A/,C C/
C.这两个三角形的面积相等
D.直线AB,A/ B/的交点不一定在MN上

题型:不详难度:| 查看答案
如图,△ABD≌△ACE,AD=8cm,AB=3cm,则BE=________cm。
题型:不详难度:| 查看答案
如图所示,有一块三角形田地,AB=AC=10m,作AB的垂直平分线ED交AC于D,交AB于E,量得BC的长是7m,请你替测量人员计算△BDC的周长为__________m。
题型:不详难度:| 查看答案
版权所有 CopyRight © 2012-2019 超级试练试题库 All Rights Reserved.