题目
题型:填空题难度:一般来源:不详
(x-1)3-x2+1 |
x-1 |
答案
∴x2-3x=2,
(x-1)3-x2+1 |
x-1 |
=
(x-1)2(x-1)-(x+1)(x-1) |
x-1 |
=(x-1)2-(x+1),
=x2-3x,
当x2-3x=2时,原式=x2-3x=2.
故本题答案为:2.
核心考点
举一反三
3 |
5 |
(2)解方程:
(x-1)2 |
x2 |
x-1 |
x |
(x-1)3-x2+1 |
x-1 |
(x-1)3-x2+1 |
x-1 |
(x-1)2(x-1)-(x+1)(x-1) |
x-1 |
3 |
5 |
(x-1)2 |
x2 |
x-1 |
x |