题目

本人在国外读a level
find the equation of the tangent to the curve y=x2-2x which is prependicular to the line y=x-3
说错了 是这一题 find the equation of the normal to the curve at te point with the given x-coordinate y=1-x2 where x=0

提问时间：2021-04-01

答案

我也在英国读书gradient=dy/dx=-2xwhen x=0,dy/dx=0,gradient of the curve=0(parallel to the x-axis)the gradient of the normal will be parallel to the y-axis& because it passes the point (0,1)therefore th...