题目

写出下列反应的离子方程式!
NAOH+HNO3 CUSO4+KOH BACO3+HCL- CU+AGNO3 CH3COOH+KOH BACL2+KCL NA2SO4+BACL2 KOH+HNO3 NAOH+H2SO4 CU(0H)2+HCL BA(OH)2+H2SO4 CH3COOH+NAOH BA(OH)2+HCL

提问时间：2021-03-13

答案

OH- + H+ =H20
CU2+ + 2 OH- = Cu(OH)2 ↓
BACO3 + 2h+ =BA2+ + H20 +CO2↑
CU+2AG+ = cu2+ + 2Ag
CH3COOH + OH- =CH3COO- + H20
BACL2+KCL 不反应
SO4 2- + BA2+ =BaSO4↓
OH- + H+ =H20
OH- + H+ =H20
OH- + H+ =H20
2OH- + 2 H + SO4 2- + BA2=H20 +BaSO4↓
CH3COOH + OH- =CH3COO- + H20
OH- + H+ =H20