题目

计算分式乘除
1、x^2-2x+1/x^2 2、2/2a+3+3/2a-3
3、x^2-2x+1/x^2-1÷x-1/x^2+x
1、（x^2-2x+1）/（x^2 ） 2、（2/2a+3）+（3/2a-3）+（2a+15）/（4a^2-9）
3、（x^2-2x+1）/（x^2-1）÷（x-1）/（x^2+x）

提问时间：2020-10-13

答案

(1)
(x^2-2x+1)/x^2
=(x-1)^2/x^2
=[(x-1)/x]^2
(2)
2/(2a+3)+3/(2a-3)+(2a+15)/(4a^2-9)
=2(2a-3)/(4a^2-9)+3(2a+3)/(4a^2-9)+(2a+15)/(4a^2-9)
=(4a+18)/(4a^2-9)
(3)
(x^2-2x+1)/(x^2-1)÷(x-1)/(x^2+x)
=(x-1)^2/[(x+1)(x-1)]÷(x-1)/[x(x+1)]
=(x-1)/(x+1)÷(x-1)/[x(x+1)]
=(x-1)*x(x+1)/[(x+1)(x-1)]
=x