当前位置: > 计算:(1)/(x-3)÷(x+2)/(x^2-9)-(1)/(x^2+5x+6)...
题目
计算:(1)/(x-3)÷(x+2)/(x^2-9)-(1)/(x^2+5x+6)

提问时间:2020-08-04

答案
1/(x-3)÷(x+2)/(x^2-9)-1/(x^2+5x+6)
=1/(x-3)÷(x+2)/[(x-3)(x+3)]-1/(x+2)(x+3)
=1/(x-3)*(x-3)(x+3)/(x+2)-1/(x+2)(x+3)
=(x+3)/(x+2)-[1/(x+2)-1/(x+3)]
=(x+3)/(x+2)-1/(x+2)+1/(x+3)
=(x+3-1)/(x+2)+1/(x+3)
=1+1/(x+3)
=(x+3+1)/(x+3)
=(x+4)/(x+3)
举一反三
已知函数f(x)=x,g(x)=alnx,a∈R.若曲线y=f(x)与曲线y=g(x)相交,且在交点处有相同的切线,求a的值和该切线方程.
我想写一篇关于奥巴马的演讲的文章,写哪一篇好呢?为什么好
奥巴马演讲不用看稿子.为什么中国领导演讲要看?
想找英语初三上学期的首字母填空练习……
英语翻译
版权所有 CopyRight © 2012-2019 超级试练试题库 All Rights Reserved.