题目
题型:填空题难度:一般来源:不详
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答案
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①若x∈[-
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②若x∈[-
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故必有ex+
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又x∈[-
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(2)当a≥0时,f(x)=ex+
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∵f(x)在x∈[-
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即a≤e2x,又e2x≥e2(-
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故答案为:[-
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核心考点
举一反三
(1)若己知函数f(x)是增函数,求实数b的取值范围;
(2)若己知b=1,求证:对任意的正整数n,不等式n<f(n)恒成立.
ax+a-x |
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(1)若f(m)=6,求f(-m)的值;
(2)若f(1)=3,求f(2)及f(
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(1)求函数f(x)的解析式;
(2)设g(x)=f(-x)-mf(x)+1,若g(x)在[-1,1]上是减函数,求实数m的取值范围.