题目
题型:单选题难度:简单来源:不详
A.{0} | B.{2} | C.{0,1,2} | D.φ |
答案
∴集合B={0,1,2},又A={-1,2},
则A∩B={2}.
故选B
核心考点
举一反三
A.4 | B.8 | C.9 | D.16 |
A.﹛2,5,9﹜ | B.﹛1,5,7﹜ | C.﹛3,7﹜ | D.﹛1,3,7﹜ |
A.{1,2} | B.{x|x≤1} | C.{-1,0,1} | D.R |
A.{0} | B.{2} | C.{0,1,2} | D.φ |
A.4 | B.8 | C.9 | D.16 |
A.﹛2,5,9﹜ | B.﹛1,5,7﹜ | C.﹛3,7﹜ | D.﹛1,3,7﹜ |
A.{1,2} | B.{x|x≤1} | C.{-1,0,1} | D.R |