题目
题型:单选题难度:简单来源:贵阳二模
x |
A.(0,2] | B.[0,2] | C.{1,2} | D.{0,1,2} |
答案
x |
则A∩B={0,1,2},
故选D.
核心考点
举一反三
A.{-2,0} | B.{2,0} | C.{-1,1,2} | D.{-2,0,2} |
A.1 | B.2 | C.3 | D.4 |
2x+1 |
x-2 |
题型:x|<1},则A∪B=( )
A.{x|
| B.{x|-1<x≤2} | ||
C.{x|-1<x<2且x≠1} | D.{x|-1<x<2} |
1 |
x |
A.[
| B.(0,
| C.(0,+∞) | D.(-∞,0)∪(
|
1 |
2 |