题目
题型:不详难度:来源:
2H2(g)+O2(g)=2H2O(l)△H=-571.6kJ•mol-1
C3H8(g)+5O2(g)=3CO2(g)+4H2O(l)△H=-2220kJ•mol-1
1mol 氢气和2mol丙烷的混合气完全燃烧时放热为( )kJ.
A.4500 | B.2791.6 | C.1681.6 | D.4725.8 |
答案
所以1mol 氢气和2mol丙烷的混合气完全燃烧时放热为285.8kJ/mol×1mol+2220kJ/mol×2=4725.8kJ,
故选D.
核心考点
试题【在一定条件下,氢气和丙烷燃烧的化学方程式为:2H2(g)+O2(g)=2H2O(l)△H=-571.6kJ•mol-1C3H8(g)+5O2(g)=3CO2(g】;主要考察你对燃烧热等知识点的理解。[详细]
举一反三
A.H2(g)+Cl2(g)=2HCl(g);△H=-184.6kJ/mol | ||
B.CH4(g)+2O2(g)=CO2(g)+2H2O(g);△H=-802.3kJ/mol | ||
C.2H2(g)+O2(g)=2H2O(l);△H=-571.6kJ/mol | ||
D.CO(g)+
|
A.C(s)+
| ||
B.2H2(g)+O2(g)═2H2O(l)△H=+571.6 kJ/mol | ||
C.CH4(g)+2O2(g)═CO2(g)+2H2O(g)△H=-890.3 kJ/mol | ||
D.C6H12O6(s)+6O2(g)═6CO2(g)+6H2O(l)△H=-2800 kJ/mol |