题目
题型：解答题难度：一般来源：不详
| 1 |
| b |
| 1 |
| c |
| 1 |
| a |
| 1 |
| c |
| 1 |
| a |
| 1 |
| b |
答案
a(
| 1 |
| b |
| 1 |
| c |
| 1 |
| a |
| 1 |
| c |
| 1 |
| a |
| 1 |
| b |
=
| a |
| b |
| a |
| c |
| b |
| c |
| b |
| a |
| c |
| a |
| c |
| b |
=
| a+c |
| b |
| a+b |
| c |
| b+c |
| a |
∵a+b+c=0，则a+b=-c，a+c=-b，b+c=-a，
∴原式=
| -b |
| b |
| -c |
| c |
| -a |
| a |
故答案为-3．
核心考点
举一反三
| x-y |
| x+y |
| 2x+1 |
| (x-1)(x+2) |
| A |
| x-1 |
| B |
| x+2 |
| 1 |
| b |
| 1 |
| c |
| 1 |
| a |
| 1 |
| c |
| 1 |
| a |
| 1 |
| b |
| 1 |
| b |
| 1 |
| c |
| 1 |
| a |
| 1 |
| c |
| 1 |
| a |
| 1 |
| b |
| a |
| b |
| a |
| c |
| b |
| c |
| b |
| a |
| c |
| a |
| c |
| b |
| a+c |
| b |
| a+b |
| c |
| b+c |
| a |
| -b |
| b |
| -c |
| c |
| -a |
| a |
| x-y |
| x+y |
| 2x+1 |
| (x-1)(x+2) |
| A |
| x-1 |
| B |
| x+2 |