题目

问一行列式题
行列式题
|x 1 1 1| |x+3 1 1 1|
|1-x x-1 1 1|=| 0 x-1 0 0|
|1-x 0 x-1 1| | 0 0 x-1 0|
|1-x 0 0 x-1| | 0 0 0 x-1|
看了半天没看懂 是怎么转化的,
上图作废 请见此图
|x.....1...1.....1|..|x+3...1...1....1|
|1-x..x-1..1....1|=|.0....x-1..0....0|
|1-x...0..x-1...1|..|.0.....0..x-1...0|
|1-x...0...0..x-1|..|.0.....0...0..x-1|
点处为空白

提问时间：2021-04-01

答案

你这题目有问题,但是一般像这样的题目,你可以把第二列,第三列,第四列分别加到第一列,得到这样的,|x.....1...1...1|..|x+3...1...1.1| |1-x..x-1..1.1| =|.2.x-1..1.1| |1-x...0..x-1...1|..|.1.0..x-1...1| |1-x...0...