题目

计算(-3ab^3c)^2(-a^2b)^3
-6a^2b(x-y)^3*1/3ab^2(y-x0
（-4x^2）（3x+1)
(-3/2x^2y-3xy^2+2)-2xy
(a+2b)(3a-4b)
(2x-3y)^2(2x+3y)^2

提问时间：2021-03-14

答案

(-3ab^3c)^2(-a^2b)^3
=9a²b^6 c²×(-a^6b³)
=-9a^8 ²b^9 c²
-6a^2b(x-y)^3*1/3ab^2(y-x)
=6*1/3*a²b(x-y)^3*ab^2(x-y)
=2a³b³(x-y)⁴
（-4x^2）（3x+1)
=（-4x^2）*3x+（-4x^2）*1
=-12x³-4x²
(-3/2x^2y-3xy^2+2)-2xy
=-3/2x²y-3xy²+2-2xy
（怀疑本题抄错了,否则太简单了,去括号即可）
(a+2b)(3a-4b)
=3a²-4ab+6ab-8b²
=3a²+2ab-8b²
(2x-3y)^2(2x+3y)^2
=[(2x-3y)(2x+3y)]²
=(4x²-9y²)²
=16x⁴-72x²y²+81y⁴