题目
亚当斯（John Couch Adams,1819-1892）,英国天文学家,海王星的发现者之一.他曾经向一个小男孩发问:"365365365365365365的平方是几?"这个小男孩咬着手指,转动着眼珠,不到一分钟,他就给出了正确答案:"13349185020851692501665829904583225."
在次请问大家,这种速算法是什么?
在次请问大家,这种速算法是什么?
提问时间：2021-01-10
答案
365365365365365365^2 = 365^2 * 1001001001001001^2
365^2 = 133225
1001001001001001^2 = 1002003004005006005004003002001
133225 * 1002003004005006005004003002001
= 133225000000000000000000000000000000
+ 000266450000000000000000000000000000
+ 000000399675000000000000000000000000
+ 000000000532900000000000000000000000
+ 000000000000666125000000000000000000
+ 000000000000000799350000000000000000
+ 000000000000000000666125000000000000
+ 000000000000000000000532900000000000
+ 000000000000000000000000399675000000
+ 000000000000000000000000000266450000
+ 000000000000000000000000000000133225
= 133491850208566925016658299941583225
365^2 = 133225
1001001001001001^2 = 1002003004005006005004003002001
133225 * 1002003004005006005004003002001
= 133225000000000000000000000000000000
+ 000266450000000000000000000000000000
+ 000000399675000000000000000000000000
+ 000000000532900000000000000000000000
+ 000000000000666125000000000000000000
+ 000000000000000799350000000000000000
+ 000000000000000000666125000000000000
+ 000000000000000000000532900000000000
+ 000000000000000000000000399675000000
+ 000000000000000000000000000266450000
+ 000000000000000000000000000000133225
= 133491850208566925016658299941583225
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