题目

1
use the factor therem to factorise the following cubics as far as possible:
f(x)=x(的三次方)-7x+6
2
find a given that (x+4) is a factor of f(x)=x(的三次方)+8x^+ax+12 and hence factorise f(x) completely.
3
show that (x-2) is a factor of f(x)=x的三次方-4x^+x+6 and hence solve f(x)=0.
4
find the three solutions to each of the following equations
10x的三次方-29x^+25x-6=0
5
the expression ax^+bx+6 has remainder 15 when divided by (x-1) and remainder 1 when divided by (x+1).find the values of a and b.
6
given that (x^-1)is a factor of x的三次方+ax^+bx -4 ,find the values of a and b

提问时间：2020-12-18

答案

-5/2(a-3)除以16/a-3+(a+3) a-5/2(a-3)除以16/a-3+（a+3)(a-3)/(a-3) a-5/2(a-3)除以(16+a^2-9)/(a-3) a-5/2(a-3)除以(7+a^2)/(a-3) a-5/2(a-3))乘以(a-3)/(7+a^2) (a-5)/ 2(7+a^2)