题目

化简：❶sin（2a+b）/sina-2cos(a+b)=sinb/sina ❷cos4a+4cos2a+3=8cos⁴a

提问时间：2020-11-16

答案

sin（2a+b）/sina-2cos(a+b)
=sina*cos(a+b)/sina+sin(a+b)cosa/sina-2cos(a+b)*sina/sina
=[sin(a+b)cosa-cos(a+b)sina]/sina
=sin(a+b-a)/sina
=sinb/sina
cos4a+4cos2a+3
=2(cos2a)^2-1+4cos2a+3
=2[(cos2a)^2+2cos2a+1]
=2[cos2a+1]^2
=2[2(cosa)^2-1+1]^2
=8(cosa)^4