题目

已知：x*x+√3y=√5,y*y+√3x=√5,且x≠y,求 y/x+x/y

提问时间：2020-11-16

答案

x*x+√3y=√5,y*y+√3x=√5x*x+√3y=y*y+√3xx*x+√3y-y*y-√3x=0(x-y)(x+y)-√3(x-y)=0(x-y)(x+y-√3)=0x≠y,x-y≠0x+y-√3=0x+y=√3(x+y)*(x+y)=3x*x+2xy+y*y=3 x*x+y*y=3-2xyx*x+√3y=√5,y*y+√3x=√5 x*x+√3y+...