题目
1.sin的三次方(-α)cos(2π+α)tan(-α-π)
2.cos(180°+α)sin(α+360°)/sin(-α-180°)cos(-180°-α)
3.sin(2π-α)cos(π+α)cos(π/2+α)sin(9π/2+α)/cos(π-α)sin(3π-α)sin(-π-α)
4.已知sinα=-3/5,求cosα,tanα的值
5.已知tanα=-根号下3,求sinα、cosα的值
2.cos(180°+α)sin(α+360°)/sin(-α-180°)cos(-180°-α)
3.sin(2π-α)cos(π+α)cos(π/2+α)sin(9π/2+α)/cos(π-α)sin(3π-α)sin(-π-α)
4.已知sinα=-3/5,求cosα,tanα的值
5.已知tanα=-根号下3,求sinα、cosα的值
提问时间:2020-11-08
答案
1.sin的三次方(-α)cos(2π+α)tan(-α-π)
解-sin的三次方(α)乘cos(α)乘(-sinα/cosα)等于sin的四次方(α)
2.cos(180°+α)sin(α+360°)/sin(-α-180°)cos(-180°-α)
解cos(α)sin(α)/-sin(α)cos(α)等于1
3.sin(2π-α)cos(π+α)cos(π/2+α)sin(9π/2+α)/cos(π-α)sin(3π-α)sin(-π-α)
解-sin(α)-cos(α)-sin(α)-cos(α)/-cos(α)sin(α)-sin(α)等于-sin(α)
4.已知sinα=-3/5,求cosα,tanα的值
解sinα=-3/5,所以cosα=4/5 或者cosα=-4/5,所以tanα=sinα/cosα=3/4 或者-3/4
5.已知tanα=-根号下3,求sinα、cosα的值
解因为tanα=sinα/cosα 和sinα的平方加cosα的平方等于1可得sinα=-根号3/2,cosα=1/2 或者 sinα=根号3/2,cosα=-1/2
解-sin的三次方(α)乘cos(α)乘(-sinα/cosα)等于sin的四次方(α)
2.cos(180°+α)sin(α+360°)/sin(-α-180°)cos(-180°-α)
解cos(α)sin(α)/-sin(α)cos(α)等于1
3.sin(2π-α)cos(π+α)cos(π/2+α)sin(9π/2+α)/cos(π-α)sin(3π-α)sin(-π-α)
解-sin(α)-cos(α)-sin(α)-cos(α)/-cos(α)sin(α)-sin(α)等于-sin(α)
4.已知sinα=-3/5,求cosα,tanα的值
解sinα=-3/5,所以cosα=4/5 或者cosα=-4/5,所以tanα=sinα/cosα=3/4 或者-3/4
5.已知tanα=-根号下3,求sinα、cosα的值
解因为tanα=sinα/cosα 和sinα的平方加cosα的平方等于1可得sinα=-根号3/2,cosα=1/2 或者 sinα=根号3/2,cosα=-1/2
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