题目
题型:单选题难度:简单来源:不详
A.(0,0.5) | B.(0.5,0.625) | C.(0.625,0.75) | D.(0.75,1) |
答案
∵f(0)=20+0-2<0;
f(0.5)=20.5+0.5-2=
2 |
f(0.625)=20.625+0.625-2>20.5+0.625-2>0;
∴f(0.5)f(0.625)<0,
f(x)=2x+x-2在区间(0.5,0.625)必有零点,
故方程2x+x=2在区间(0.5,0.625)必有一根
故答案为 B
核心考点
试题【若x0是方程式 2x+x=2的解,则x0属于区间( )A.(0,0.5)B.(0.5,0.625)C.(0.625,0.75)D.(0.75,1)】;主要考察你对函数的零点存在定理等知识点的理解。[详细]
举一反三
1 |
1-x |
A.f(x1)<0,f(x2)<0 | B.f(x1)<0,f(x2)>0 |
C.f(x1)>0,f(x2)<0 | D.f(x1)>0,f(x2)>0 |
A.(-2,-1) | B.(-1,0) | C.(0,1) | D.(1,2) |
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