题目
题型:单选题难度:简单来源:不详
2x-x2 |
A.(0,2) | B.[0,2] | C.(1,2] | D.(0,2] |
答案
2x-x2 |
B={y|y=2x}={y|y>0}
∴A∩B={x|0<x<2}
故选D.
核心考点
举一反三
A.M∩N | B.(C∪M)∩(C∪N) | C.(C∪M)∪(C∪N) | D.M∪N |
2x-x2 |
A.(0,2) | B.[0,2] | C.(1,2] | D.(0,2] |
2x-x2 |
A.M∩N | B.(C∪M)∩(C∪N) | C.(C∪M)∪(C∪N) | D.M∪N |