题目
题型:填空题难度:一般来源:不详
kπ |
2 |
π |
3 |
答案
kπ |
2 |
π |
3 |
4 |
3 |
8 |
3 |
∴k=-1,0,1,2,即α=-
5 |
6 |
π |
3 |
π |
6 |
2 |
3 |
则M∩N={-
5 |
6 |
π |
3 |
π |
6 |
2 |
3 |
故答案为:{-
5 |
6 |
π |
3 |
π |
6 |
2 |
3 |
核心考点
举一反三
A.-1 | B.{-1} | C.{5,-1} | D.{1,-1} |
A.|a|≤1 | B.|a|>1或0<|a|<1 | C.a>1 | D.a>1或a<0 |
(1)求A,B
(2)求CR(A∩B)
kπ |
2 |
π |
3 |
kπ |
2 |
π |
3 |
4 |
3 |
8 |
3 |
5 |
6 |
π |
3 |
π |
6 |
2 |
3 |
5 |
6 |
π |
3 |
π |
6 |
2 |
3 |
5 |
6 |
π |
3 |
π |
6 |
2 |
3 |
A.-1 | B.{-1} | C.{5,-1} | D.{1,-1} |
A.|a|≤1 | B.|a|>1或0<|a|<1 | C.a>1 | D.a>1或a<0 |