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题目
题型:解答题难度:一般来源:不详
4x2-y2
x2-4y2
-
(2x-y)2
x2-4y2
-
2y2-4xy
4y2-x2
答案
原式=
4x2-y2
x2-4y2
-
(2x-y)2
x2-4y2
+
2y2-4xy
x2-4y2

=
4x2-y2-4x2+4xy-y2+2y2-4xy
x2-4y2

=
0
x2-4y2

=0.
核心考点
试题【4x2-y2x2-4y2-(2x-y)2x2-4y2-2y2-4xy4y2-x2.】;主要考察你对分式的加减运算等知识点的理解。[详细]
举一反三
4
x2-1
-
x+1
x-1
题型:解答题难度:一般| 查看答案
2x2+1
x2-5x+6
-
x2-1
x2-5x+6
+
4-5x
x2-5x+6
题型:解答题难度:一般| 查看答案
x+y
x-y+z
+
x+z
y-x-z
-
y+z
z+x-y
题型:解答题难度:一般| 查看答案
x-1
x+1
=M+
N
x+1
,则M+N的值为(  )
A.-1B.1C.-2D.2
题型:单选题难度:简单| 查看答案
先阅读下列材料,再解答后面的问题.
1
1×3
=
1
2
(1-
1
3
)
1
3×5
=
1
2
(
1
3
-
1
5
)
1
5×7
=
1
2
(
1
5
-
1
7
)
,…,
1
17×19
=
1
2
(
1
17
-
1
19
)

1
1×3
+
1
3×5
+
1
5×7
+…+
1
17×19

=
1
2
(1-
1
3
)+
1
2
(
1
3
-
1
5
)+
1
2
(
1
5
-
1
7
)+…+
1
2
(
1
17
-
1
19
)

=
1
2
(1-
1
3
+
1
3
-
1
5
+
1
5
-
1
7
+…+
1
17
-
1
19
)

=
1
2
(1-
1
19
)=
9
19

(1)在和式
1
1×3
+
1
3×5
+
1
5×7
+
…中,第五项为______,第n项为______;
(2)计算
1
(x-1)x
+
1
x(x+1)
+
1
(x+1)(x+2)
+
1
(x+2)(x+3)
题型:解答题难度:一般| 查看答案
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