题目

JTable(Vector rowData,Vector columnNames)
package table;
public class grade
{
String name;
int china;
int math;
int all;
boolean ok;
public grade(String name,int china,int math,int all,boolean ok)
{
this.name = name;
this.china = china;
this.math = math;
this.all = all;
this.ok = ok;
}
}
package table;
import java.awt.BorderLayout;
import java.awt.Dimension;
import java.util.Vector;
import javax.swing.*;
public class table
{
public table()
{
JFrame f=new JFrame();
Vector va=new Vector();
grade gr1=new grade("网鹏",new Integer(82),new Integer(91),new Integer(100),new Boolean(true));
grade gr2=new grade("网",new Integer(82),new Integer(91),new Integer(100),new Boolean(true));
grade gr=new grade("鹏",new Integer(82),new Integer(91),new Integer(100),new Boolean(true));
va.addElement(gr);
va.addElement(gr2);
va.addElement(gr1);
Vector ve=new Vector();<

提问时间：2021-03-28

答案

你的Vector va=new Vector()里面的数据类型都是grade的,而grade又不是数组,所以你的va里面都是一个一个的grade对象,JTable不会自动解析你的grade的构造方法,把它变成String数组,所以你要手动提取出gr1,gr2,gr3中你所...