题目

(-1/2m^2-1/3mn+1)·(-1/4m^3n)
只要答案就行正在纠结算法阿~

提问时间：2021-03-17

答案

(-1/2m^2-1/3mn+1)·(-1/4m^3n)
=(1/2m^2+1/3mn-1)(1/4m^3n)
=(1/2·1/4)m^(2+3)n+(1/3·1/4)m^(1+3)n^(1+1)-1/4m^3n
=(1/8)m^5n+(1/12)m^4n^2-1/4m^3n