题目

八阶行列式怎么展开?
有道程序题,要求八阶行列式的值,我把它展开如下
bh(0) = ah(0, 0) * ah(1, 1) * ah(2, 2) * ah(3, 3) * ah(4, 4) * ah(5, 5) * ah(6, 6) * ah(7, 7) - ah(7, 0) * ah(6, 1) * ah(5, 2) * ah(4, 3) * ah(3, 4) * ah(2, 5) * ah(1, 6) * ah(0, 7)
bh(1) = ah(1, 0) * ah(2, 1) * ah(3, 2) * ah(4, 3) * ah(5, 4) * ah(6, 5) * ah(7, 6) * ah(0, 7) - ah(6, 0) * ah(5, 1) * ah(4, 2) * ah(3, 3) * ah(2, 4) * ah(1, 5) * ah(0, 6) * ah(7, 7)
bh(2) = ah(2, 0) * ah(3, 1) * ah(4, 2) * ah(5, 3) * ah(6, 4) * ah(7, 5) * ah(0, 6) * ah(1, 7) - ah(5, 0) * ah(4, 1) * ah(3, 2) * ah(2, 3) * ah(1, 4) * ah(0, 5) * ah(7, 6) * ah(6, 7)
bh(3) = ah(3, 0) * ah(4, 1) * ah(5, 2) * ah(6, 3) * ah(7, 4) * ah(0, 5) * ah(1, 6) * ah(2, 7) - ah(4, 0) * ah(3, 1) * ah(2, 2) * ah(1, 3) * ah(0, 4) * ah(7, 5) * ah(6, 6) * ah(5, 7)
bh(4) = ah(4, 0) * ah(5, 1) * ah(6, 2) * ah(7, 3) * ah(0, 4) * ah(1, 5) * ah(2, 6) * ah(3, 7) - ah(3, 0) * ah(2, 1) * ah(1, 2) * ah(0, 3) * ah(7, 4) * ah(6, 5) * ah(5, 6) * ah(4, 7)
bh(5) = ah(5, 0

提问时间：2021-02-12

答案

如果是展开就展开的公式降阶就是了·······麻烦的话!直接简化成上（下）三角阵来解嘛!