题目

OC,OD均为角AOB内任意两条射线,OM平分角AOD,ON平分角COB,角AOB=100°角DOC=20°.求角MON度数.

提问时间：2021-01-27

答案

MON=MOD+DOC+CON
=1/2AOM+DOC+1/2COB
=1/2(AOM+COB)+DOC
=1/2(AOB-DOC)+DOC
=1/2*(100°-20°)+20°
=40°+20°
=60°
答:角MON为60°