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题目
分解因式:[4/(x^2-y^2)+(x+y)/(xy^2-x^2y)]÷(x^2+xy-2y^2)/(x^2y+2xy^2)

提问时间:2021-01-25

答案
=[4/(x+y)(x-y)-(x+y)/xy(x-y)]÷(x+2y)(x-y)/xy(x+y)=(4xy-x²-2xy-y²)/xy(x+y)(x-y)×xy(x+y)/(x+2y)(x-y)=-(x-y)²/(x-y)×1/(x+2y)(x-y)=-1/(x+2y)
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