题目
用适当方法解下列方程
(1)x2-10x+25=7;
(2)(x-1)2+2x(x-1)=0.
(1)x2-10x+25=7;
(2)(x-1)2+2x(x-1)=0.
提问时间:2021-01-12
答案
(1)x2-10x+25=7,
移项得:x2-10x+18=0,
b2-4ac=(-10)2-4×1×18=28,
∴x=
移项得:x2-10x+18=0,
b2-4ac=(-10)2-4×1×18=28,
∴x=
10±
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