题目

当2a+b/3a-b=2时,求代数式2a+b/2(3a-b)+3a-b/3(2a+b)
(1)当2a+b/3a-b=2时,求代数式2a+b /2(3a-b) + 3a-b/3(2a+b)
(2)若代数式-2^nb^m+2与4/5a^5b^2-3m是同类项,则m=___,n=___
代数式-2^nb^m+2与4/5a^5b^2-3m (负2的N次方乘B的M次方+2与5分之4乘a的5次方乘B的2-3M次方)

提问时间：2021-01-03

答案

(2a+b)/(3a-b)=22a+b=6a-2b4a=3ba=3b/4代入(2a+b)/[2(3a-b)]+(3a-b)/[3(2a+b)]=(2*3b/4+b)/[2(3*3b/4-b)]+(3*3b/4-b)/[3(2*3b/4+b)]=(5b/2)/(5b/2)+(5b/4)/(15b/2)=1+1/6=7/6-a^nb^(m+2)与4/5a^5b^(2-3m)是同类项则a...