题目

f(x)=log^2(x+1)/(x-1)+log^2(x-1)+log^2(p-x)的值域（负无穷,log^(p+1)^2/4],则p的取值范围是?
对称轴应该大于1吧？要不然取不到最大值，p/2大于1，所以p应该大于3吧

提问时间：2020-11-21

答案

f(x)=log^2(x+1)/(x-1)+log^2(x-1)+log^2(p-x)定义域：(x+1)/(x-1)＞0,且x-1＞0,且p-x＞0x＜-1或x＞1,且x＞1,且x＜p∴1＜x＜pf(x)=log2 (x+1)/(x-1)+log2 (x-1)+log2 (p-x)=log2 [(x+1)/(x-1) * (x-1) * (p-x) ]=lo...