题目
1.(x-y)^2-4(x-y+3)
2.36a^2-25b^2-10b-1
3.ax^2+bx^2+bx+ax+cx^2+cx
4.x^2-12xy+36y^2-6x+36y+8
5.4-x^2+2xy-y^2
2.36a^2-25b^2-10b-1
3.ax^2+bx^2+bx+ax+cx^2+cx
4.x^2-12xy+36y^2-6x+36y+8
5.4-x^2+2xy-y^2
提问时间:2020-10-30
答案
1、(x-y)^2-4(x-y+3)
=(x-y)^2-4(x-y)-12
=(x-y+2)(x-y-6)
2、36a^2-25b^2-10b-1
=(6a)^2-[(5b)^2+10b+1]
=(6a)^2-(5b+1)^2
=(6a+5b+1)(6a-5b-1)
3、ax^2+bx^2+bx+ax+cx^2+cx
=ax(x+1)+bx(x+1)+cx(x+1)
=(ax+bx+cx)(x+1)
4、x^2-12xy+36y^2-6x+36y+8
=(x-6y)^2-6(x-6y)+8
=(x-6y-2)(x-6y-4)
5、4-x^2+2xy-y^2
=4-(x^2-2xy+y^2)
=4-(x-y)^2
=(2+x-y)(2-x+y)
=(x-y)^2-4(x-y)-12
=(x-y+2)(x-y-6)
2、36a^2-25b^2-10b-1
=(6a)^2-[(5b)^2+10b+1]
=(6a)^2-(5b+1)^2
=(6a+5b+1)(6a-5b-1)
3、ax^2+bx^2+bx+ax+cx^2+cx
=ax(x+1)+bx(x+1)+cx(x+1)
=(ax+bx+cx)(x+1)
4、x^2-12xy+36y^2-6x+36y+8
=(x-6y)^2-6(x-6y)+8
=(x-6y-2)(x-6y-4)
5、4-x^2+2xy-y^2
=4-(x^2-2xy+y^2)
=4-(x-y)^2
=(2+x-y)(2-x+y)
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