题目
(x²-1)²+6(1-x²)+9 分解因式
提问时间:2020-10-30
答案
( x" - 1 )" + 6( 1 - x" ) + 9
= ( x" - 1 )" - 2X 3( x" - 1 ) + 3"
= ( x" - 1 - 3 )"
= ( x" - 4 )"
= ( x + 2 )"( x - 2 )"
或者
= ( 1 - x" )" + 2X 3( 1 - x" ) + 3"
= ( 1 - x" + 3 )"
= ( 4 - x" )"
= ( 2 - x )"( 2 + x )"
= ( x - 2 )"( x + 2 )"
= ( x" - 1 )" - 2X 3( x" - 1 ) + 3"
= ( x" - 1 - 3 )"
= ( x" - 4 )"
= ( x + 2 )"( x - 2 )"
或者
= ( 1 - x" )" + 2X 3( 1 - x" ) + 3"
= ( 1 - x" + 3 )"
= ( 4 - x" )"
= ( 2 - x )"( 2 + x )"
= ( x - 2 )"( x + 2 )"
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