题目

【【【急】】】分式计算x^2-x-6/x-3 ÷ x-3/x^2-5x+6
x^2-x-6/x-3 ÷ x-3/x^2-5x+6

提问时间：2020-10-19

答案

原式=[(x²-x-6)/(x-3)]÷[(x-3)/(x²-5x+6)]
={[(x+2)(x-3)]/(x-3)}÷{(x-3)/[(x-2)(x-3)]}
=(x+2)÷[1/(x-2)]
=(x+2)×(x-2)
=x²-4