题目
log(√2+1)(3+2√2)+log√3(√6+3√3)-log3(2+√3)=
提问时间:2020-08-07
答案
原式=log(√2+1)[(√2+1)²]+log3[(√6+3√3)²÷(2+√3)]
=2log(√2+1)(√2+1)+log3[(33+12√2)÷(2+√3)]
=2+log3[(33+12√2)/(2+√3)]
你写错了
=2log(√2+1)(√2+1)+log3[(33+12√2)÷(2+√3)]
=2+log3[(33+12√2)/(2+√3)]
你写错了
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