题目

x-3/2+y-2/3=4 x-3/2-y-2/3=2 用加减消元法解方程组

提问时间：2020-07-13

答案

x-3/2+y-2/3=4 (1)
x-3/2-y-2/3=2 (2)
(1)+(2) 得,2x - 2*3/2 -2 *2/3 =6;
x =31/6;
(1)-(2) 得,2y =2;
y=1;