题目
已知|X+3|+(b-3/I)的平方=0化简多项式3x平方y-[2xy平凡-2(XY-2/3X平凡y)-XY]+3xy平方
提问时间：2020-05-22
答案
|x+3|+(y-1/3)的平方=0
|x+3|=0,(y-1/3)的平方=0
x=-3
y=1/3
3x²y-[2xy²-2(xy-2/3x²y)-xy]+3xy²
=3x²y-[2xy²-2xy+4/3x²y-xy]+3xy²
=3x²y-[2xy²-2xy-xy+4/3x²y]+3xy²
=3x²y-[2xy²-3xy+4/3x²y]+3xy²
=3x²y-2xy²+3xy-4/3x²y+3xy²
=3x²y-4/3x²y+3xy²-2xy²+3xy
=5/3x²y+xy²+3xy
=xy(5/3x+y+3)
=-3*1/3*[5/3*(-3)+1/3+3]
=-(-5+4/3)
=-(-11/3)
=11/3
|x+3|=0,(y-1/3)的平方=0
x=-3
y=1/3
3x²y-[2xy²-2(xy-2/3x²y)-xy]+3xy²
=3x²y-[2xy²-2xy+4/3x²y-xy]+3xy²
=3x²y-[2xy²-2xy-xy+4/3x²y]+3xy²
=3x²y-[2xy²-3xy+4/3x²y]+3xy²
=3x²y-2xy²+3xy-4/3x²y+3xy²
=3x²y-4/3x²y+3xy²-2xy²+3xy
=5/3x²y+xy²+3xy
=xy(5/3x+y+3)
=-3*1/3*[5/3*(-3)+1/3+3]
=-(-5+4/3)
=-(-11/3)
=11/3
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