题目
题型:不详难度:来源:
2
| ||
3 |
答案
x2 |
a2 |
y2 |
b2 |
由题设,中心在坐标原点的椭圆过点(1,
2
| ||
3 |
∴
1 |
a2 |
| ||
b2 |
a2 |
c |
三式联立可以解得a=
3 |
2 |
7 |
| ||
3 |
7 |
3 |
故该椭圆的方程为
x2 |
3 |
y2 |
2 |
x2 |
7 |
y2 | ||
|
故应填
x2 |
3 |
y2 |
2 |
x2 |
7 |
y2 | ||
|
核心考点
举一反三
2
| ||
3 |
x2 |
a2 |
y2 |
b2 |
2
| ||
3 |
1 |
a2 |
| ||
b2 |
a2 |
c |
3 |
2 |
7 |
| ||
3 |
7 |
3 |
x2 |
3 |
y2 |
2 |
x2 |
7 |
y2 | ||
|
x2 |
3 |
y2 |
2 |
x2 |
7 |
y2 | ||
|